Mean Deviation about Median:
The mean deviation about median is the mean of the absolute deviations of a set of data about the median of the data.For Ungrouped data:
- Ungrouped data is the raw data we gather from an experiment or study initially.
- The data is raw — that is, it's not sorted into categories, classified, or otherwise grouped.
- An ungrouped set of data is basically a list of numbers.
Let n observations be x1, x2, x3, ...,xn.
Steps to calculate mean deviation about median for ungrouped data:
Step 1:
Calculate the measure of central tendency about which we are to find the mean deviation. Let it be 'a'.
Step 2:
Find the deviation of each xi from a, i.e., x1-a, x2-a, x3-a, ...,xn-a.
Step 3:
Find the absolute values of the deviations, i.e., drop the minus sign (-), if it is there, i.e., |x1-a|, |x2-a|, |x3-a|, ...,|xn-a|
Step 4:
Find the median of the absolute values of the deviations. This median is the mean deviation about a.
=Σ|xn-a|/n
Mean Deviation about median =Σ|xn-M|/n
Example 1
Find the mean deviation about the median for the following data:
6, 7, 10, 12, 13, 4, 8, 12
Solution:
We proceed step-wise and get the following:
Step 1:
Median of the given data is:= 4,6,7,8, 10, 12, 12, 13
Median(for odd Numbers)=nth/2 term
Median(for even Numbers)= {nth+(n+1)th}/2 term
Median=(8+10)/2
=9
Example 1
Find the mean deviation about the median for the following data:
6, 7, 10, 12, 13, 4, 8, 12
Solution:
We proceed step-wise and get the following:
Step 1:
Median of the given data is:= 4,6,7,8, 10, 12, 12, 13
Median(for odd Numbers)=nth/2 term
Median(for even Numbers)= {nth+(n+1)th}/2 term
Median=(8+10)/2
=9
Step 2:
The deviations of the respective observations from the median M, i.e.,xi-M are
6–9,7-9, 10-9, 12-9, 13–9,4–9,8–9, 12-9
or -3, -2, 1, 3, 4, -5, -1,3
Step 3:
The absolute values of the deviations, i.e., (xi-M| are
3,2,1,3,4,5,1,3
Step 4:
The required mean deviation about the median is = Σ|xi-M|/n
=(3+2+1+3+4+5+1+3)/8
=2.75