How to calculate probability?
In our day to day life we use many words about the chances of occurrence of events.
Probability theory attempts to quantify these chances of occurrence or non occurrence of events.
Probability : Numbers Related problems
Problems based on number probability are explained here with the help of different examples.We learn here how to make different digit numbers from given numbers.
Short symbols for
1. Number of probability = n(p)
2. Expected number of Events = ENE
3. Total Number of Events = TNE
n(p) = ENE/ TNE
For Example
How many new numbers can be formed using 4,5,7,4,8,6,3,5,5?
Case 1:
How many new numbers can be formed using 4,5,7,4,8,6,3,5,5?
Case 1:
To calculate probability when numbers can take any position
Sol:
Total digits(4,5,7,4,8,6,3,5,5) = 9
Occurrence of number 4 =2
Occurrence of number 5 =3
Expected number of Events (ENE)
= 9!/2!.3!
=9×8×7×6×5×4×3!/2×1×3!
=30240
New numbers which can be formed using 4,5,7,4,8,6,3,5,5(when numbers can take any position) =30240
To calculate probability when all Even Numbers lie together
Sol:
Number are=5,7,3,5,5,4486(here all even numbers counted as 1)
Total digits(5,7,3,5,5,4486) = 6
Occurrence of number 4 = 2
Occurrence of number 5 = 3
Expected number of Events = ENE
=6!/3! × 4!/2!
Case 3:
Numbers which can be formed using 4,5,7,4,8,6,3,5,5 (when numbers can take any position) - Numbers which can be formed using 4,5,7,4,8,6,3,5,5(All Even Numbers lie together)
=30240-1440
=6×5×4×3!/3! × 4×3×2!/2!
=120× 20
=1440
=120× 20
=1440
Case 3:
To calculate probability when No Even Numbers lie together
Sol:Numbers which can be formed using 4,5,7,4,8,6,3,5,5 (when numbers can take any position) - Numbers which can be formed using 4,5,7,4,8,6,3,5,5(All Even Numbers lie together)
=30240-1440
=28800
Case 4:
Number are = 57355,4,4,8,6 (here all odd numbers counted as 1)
Total digits(57355,4,4,8,6) = 5
Occurrence of number 4 =2
Occurrence of number 5 =3
=5×4×3!/3! × 5×4×3×2!/2!
Case 5:
Numbers which can be formed using 4,5,7,4,8,6,3,5,5 (when numbers can take any position) -
Case 4:
To calculate probability when all Odd Numbers lie together
Sol:Number are = 57355,4,4,8,6 (here all odd numbers counted as 1)
Total digits(57355,4,4,8,6) = 5
Occurrence of number 4 =2
Occurrence of number 5 =3
Expected number of Events = ENE= 5!/3! × 5!/2!
=5×4×3!/3! × 5×4×3×2!/2!
=20× 60
=1200
=1200
Case 5:
To calculate probability when No Odd Numbers lie together
Numbers which can be formed using 4,5,7,4,8,6,3,5,5 (when numbers can take any position) -
Numbers which can be formed using 4,5,7,4,8,6,3,5,5(All Odd Numbers lie together)
=30240-1200
=29040
=30240-1200
=29040