NCERT Solutions For Class 7 Maths Chapter 13 – Exponents and Powers
Question 1. Find the value of:
(i) 26
Solution:-
26 = 2 × 2 × 2 × 2 × 2 × 2 = 64
(ii) 93
Solution:-
93 = 9 × 9 × 9 = 729
(iii) 112
Solution:-
112 = 11 × 11 = 121
(iv) 54
Solution:-
54 = 5 × 5 × 5 × 5 = 625
Question 2. Express the following in exponential form:
(i) 6 × 6 × 6 × 6 = 64
(ii) t × t = t2
(iii) b × b × b × b = b4.
(iv) 5 × 5× 7 × 7 × 7 = 52 × 72.
(v) 2 × 2 × a × a = 22 × a2.
(vi) a × a × a × c × c × c × c × d = a3 × c4 × d.
Question 3. Express each of the following numbers using exponential notation:
Solution:-
(i) 512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 29
(ii) 343 = 7 × 7 × 7= 73.
(iii) 729 = 3 × 3 × 3 × 3 × 3 × 3= 36.
(iv) 3125 = 5 × 5 × 5 × 5 × 5= 55.
Question 4. Identify the greater number, wherever possible, in each of the following?
(i) 43 or 34
Solution:-
The expansion of 43 = 4 × 4 × 4 = 64
The expansion of 34 = 3 × 3 × 3 × 3 = 81
Clearly,
64 < 81
So, 43 < 34
Hence 34 is the greater number.
(ii) 53 or 35
Solution:-
The expansion of 53 = 5 × 5 × 5 = 125
The expansion of 35 = 3 × 3 × 3 × 3 × 3= 243
125 < 243
So, 53 < 35
Hence 35 is the greater number.
(iii) 28 or 82
Solution:-
The expansion of 28 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 256
The expansion of 82 = 8 × 8= 64
Clearly,
256 > 64
So, 28 > 82
Hence 28 is the greater number.
(iv) 1002 or 2100
Solution:-
The expansion of 1002 = 100 × 100 = 10000
The expansion of 210 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 1024
(210)10= 1024 × 1024 ×1024 × 1024 ×1024 × 1024 × 1024 × 1024 × 1024 × 1024 =
Clearly,
1002 < 2100
Hence 2100 is the greater number.
(v) 210 or 102
Solution:-
The expansion of 210 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 1024
The expansion of 102= 10 × 10= 100
Clearly,
1024 > 100
So, 210 > 102
Hence 210 is the greater number.
Question 5. Express each of the following as product of powers of their prime factors:
(i) 648
Solution:-
Factors of 648 = 2 × 2 × 2 × 3 × 3 × 3 × 3 = 23 × 34
(ii) 405
Solution:-
Factors of 405 = 3 × 3 × 3 × 3 × 5= 34 × 5
(iii) 540
Solution:-
Factors of 540 = 2 × 2 × 3 × 3 × 3 × 5 = 22× 33× 5
(iv) 3,600
Solution:-
Factors of 3600 = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5 = 24× 32× 52
Question 6. Simplify:
(i) 2 × 103
Solution:-
2 × 103 = 2 × 10 × 10 × 10
= 2 × 1000
= 2000
(ii) 72 × 22
Solution:-
72 × 22 = 7 × 7 × 2 × 2
= 49 × 4
= 196
(iii) 23× 5
Solution:-
23× 5 = 2 × 2 × 2 × 5
= 8 × 5
= 40
(iv) 3 × 44
Solution:-
3 × 44 = 3 × 4 × 4 × 4 × 4
= 3 × 256
= 768
(v) 0 × 102
Solution:-
0 × 102 = 0 × 10 × 10
= 0 × 100
= 0
(vi) 52 × 33
Solution:-
52 × 33 = 5 × 5 × 3 × 3 × 3
= 25 × 27
= 675
(vii) 24 × 32
Solution:-
24 × 32 = 2 × 2 × 2 × 2 × 3 × 3
= 16 × 9
= 144
(viii) 32 × 104
Solution:-
32 × 104= 3 × 3 × 10 × 10 × 10 × 10
= 9 × 10000
= 90000
Question 7. Simplify:
(i) (– 4)3
Solution:-
The expansion of (– 4)3
= – 4 × – 4 × – 4
= – 64
(ii) (–3) × (–2)3
Solution:-
The expansion of (–3) × (–2)3
= – 3 × – 2 × – 2 × – 2
= – 3 × – 8
= 24
(iii) (–3)2 × (–5)2
Solution:-
The expansion of (–3)2 × (–5)2
= – 3 × – 3 × – 5 × – 5
= 9 × 25
= 225
(iv) (–2)3 × (–10)3
Solution:-
The expansion of (–2)3 × (–10)3
= – 2 × – 2 × – 2 × – 10 × – 10 × – 10
= – 8 × – 1000
= 8000
(i) 2.7 × 1012 ; 1.5 × 108
Solution:-
Comparing the exponents of base 10,
Clearly,
2.7 × 1012 > 1.5 × 108
(ii) 4 × 1014 ; 3 × 1017
Solution:-
By observing the question
Comparing the exponents of base 10,
Clearly,
4 × 1014 < 3 × 1017